PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]

[[R-DEV]Chuc]

Taken while I was on my trip..

[georgehu2007]

Those pictures are from Japan, right? LOL
where in Japan did you visit?

[[R-DEV]Chuc]

Tokyo, Kyoto and Kawaguchiko, the pics above were from Fuyukomi (Winter Comic Market)

[youm0nt]

[Ghostrider]

Originally Posted by Teek

= (An + 2AB + Bn)

Originally Posted by e-Gor

Erm...No

(a + b)^2
= (a + b) (a + b)
= a^2 + ab + ba + b^2
= a^2 + 2ab + b^2

(a^2 + 2ab + b^2) != (an + 2ab + bn)

@Teek: Hope its cleared

~xghost();

[Liquid_Cow]

Originally Posted by Ghostrider

Hope its cleared

You gotta get out of your room more often Ghost

[georgehu2007]

Originally Posted by Ghostrider

(a + b)^2
= (a + b) (a + b)
= a^2 + ab + ba + b^2
= a^2 + 2ab + b^2

(a^2 + 2ab + b^2) != (an + 2ab + bn)

@Teek: Hope its cleared

~xghost();

i looked up (a+b)^n in a math book, and the expanded form is much more complicated than that. (a+b)^n = a^n + na^(n-1)b + .......
it is a very long equation. go ahead, look it up in a math book. you'll see.
and the 2ab part only applies to (a + b)^2

[Sabre_tooth_tigger]

Sounds like high school math but then Ive forgotten all mine so I wont argue

[Teek]

Originally Posted by georgehu2007

i looked up (a+b)^n in a math book, and the expanded form is much more complicated than that. (a+b)^n = a^n + na^(n-1)b + .......
it is a very long equation. go ahead, look it up in a math book. you'll see.
and the 2ab part only applies to (a + b)^2

no its not, I did it 10 times today. What I posted is the short formula for finding it without doing the math ghostrider did everytime.
The 2ab in this case could be (n)(ab)

[georgehu2007]

then you are saying (a+b)^n = a^n +nab + b^n?

take a look at the following:
(a+b)^0 = 1
(a+b)^1 = a + b
(a+b)^2 = a^2 + 2ab + b^2
(a+b)^3 = a^3 + 3a^2b + 3ab^3 + b^3
if n increases by one, then the number of terms in the expanded form also increases by one. let's say n = 42, then the number of terms would be 43.
so only if n = 2 would the number of terms be three. look in an algebra or calculus book and you'll find a very long equation. end of discussion