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#351 |
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PR Art Team
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![]() ![]() ![]() Taken while I was on my trip.. |
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#352 |
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
Those pictures are from Japan, right? LOL
where in Japan did you visit? |
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Pretty...pretty badass.
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#353 |
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PR Art Team
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
Tokyo, Kyoto and Kawaguchiko, the pics above were from Fuyukomi (Winter Comic Market)
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#354 |
![]() Join Date: Mar 2007
Posts: 2,680
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
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(o,o) |)__) -"-"- O RLY? |
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#355 |
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Retired PR Developer
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Location: P.R.
Posts: 2,559
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
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Young Americans Doc: Link || Working for Love & World Peace
For those Interested in the E vs C Topic: CSC Book || CSE Seminar || Polonium Halos Some FAQs CSC FAQ. || CSE Articles || Published Reports |
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#356 |
![]() Join Date: Feb 2007
Location: In the Pasture
Posts: 934
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
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Fear the Moo!!! <MFF> |
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#357 | |
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
Quote:
it is a very long equation. go ahead, look it up in a math book. you'll see. and the 2ab part only applies to (a + b)^2 | |
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Pretty...pretty badass.
![]() Help me raise my Habamon! |
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#358 |
![]() Join Date: Jun 2007
MontserratPosts: 1,698
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
Sounds like high school math but then Ive forgotten all mine so I wont argue
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#359 | |
![]() Join Date: Dec 2006
CanadaLocation: Vancouver
Posts: 2,665
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
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The 2ab in this case could be (n)(ab) | |
Determined bomber[R-DEV]RikiRude: Hehe I think Teek is on the money [TT]engineer: Wow, camo that doesn't look like the designers took a dump on a piece of canvas and shouted "BRILLIANT!". |
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#360 |
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Re: PR is a Realism Mod - Hence *Silly Pictures Thread* [Language][Pic Heavy]
then you are saying (a+b)^n = a^n +nab + b^n?
take a look at the following: (a+b)^0 = 1 (a+b)^1 = a + b (a+b)^2 = a^2 + 2ab + b^2 (a+b)^3 = a^3 + 3a^2b + 3ab^3 + b^3 if n increases by one, then the number of terms in the expanded form also increases by one. let's say n = 42, then the number of terms would be 43. so only if n = 2 would the number of terms be three. look in an algebra or calculus book and you'll find a very long equation. end of discussion |
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Pretty...pretty badass.
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| heavy, languagepic, mod, pictures, realism, silly, thread |
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